Shop Online


Follow Us
Facebook Twitter
Latest News

Click here for our Latest News

Print-Friendly Page

Barrette's Small Engines Inc. - FAQ's

How is log splitter force measured?

All of our log splitters use similar two-stage pump systems with a pressure check valve in the first stage. Engines used in log splitter applications will produce ample pressure needed to cycle the first check valve in the pump. Increased engine displacement and torque equals less strain on the engine and theoretically a longer engine life should result. The larger displacement and torque engines are essentially looking at getting more usage hours out of the engine and not more log splitter output force.

The output force on the discharge side of the pump multiplied by the area of that applied force is what will ultimately determine the log splitters applied output force. If the pumps are essentially equal, it will be variances in the diameter of the cylinder, factored with the output pressure of the pump, that will determine to log splitters maximum output force.

Fact #1 - The log splitter pumps have a maximum output pressure range of 3,000 - 3,200 psi.

Fact #2 - The formula for the area of a circle is: Area = 3.14 x (radius of the circle squared).

Example Calculation : Using a 5" diameter* cylinder (*radius equals 1/2 diameter), we can see that a 5" diameter cylinder would have a cross cylinder circular surface area of (3.14) x (2.5")(2.5"). This would equate to a cross cylindrical surface area of 19.63  If we multiply the 3,000 psi times the cross cylindrical surface area of the 5" cylinder, we have a resulting calculated hydraulic output force of the cylinder, whicch in this example would be equal to approximately 58,890 pounds (~30 tons).

Shipping Policy | Return Policy | Privacy Policy | Terms Website design and hosting by
Barrette's Small Engines Illustrated Part Diagrams Click here for Hot Deals! View Cart Checkout Tell a Friend Bookmark Our Site Decrease Font Size Increase Font Size